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-x^2+3600=0
We add all the numbers together, and all the variables
-1x^2+3600=0
a = -1; b = 0; c = +3600;
Δ = b2-4ac
Δ = 02-4·(-1)·3600
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*-1}=\frac{-120}{-2} =+60 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*-1}=\frac{120}{-2} =-60 $
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